Math, asked by choudharyaditya949, 8 months ago

(x2+4-2x) (x2+4+2x)

Answers

Answered by pukultanvi4444
0

Answer :

x4+4x2+16

Step by step

(x2+4−2x)(x2+4+2x)

(x2+4−2x)(x2+4+2x)=(x2+4+−2x)(x2+4+2x)

(x2+4−2x)(x2+4+2x)=(x2+4+−2x)(x2+4+2x)=(x2)(x2)+(x2)(4)+(x2)(2x)+(4)(x2)+(4)(4)+(4)(2x)+(−2x)(x2)+(−2x)(4)+(−2x)(2x)

(x2+4−2x)(x2+4+2x)=(x2+4+−2x)(x2+4+2x)=(x2)(x2)+(x2)(4)+(x2)(2x)+(4)(x2)+(4)(4)+(4)(2x)+(−2x)(x2)+(−2x)(4)+(−2x)(2x)=x4+4x2+2x3+4x2+16+8x−2x3−8x−4x2

(x2+4−2x)(x2+4+2x)=(x2+4+−2x)(x2+4+2x)=(x2)(x2)+(x2)(4)+(x2)(2x)+(4)(x2)+(4)(4)+(4)(2x)+(−2x)(x2)+(−2x)(4)+(−2x)(2x)=x4+4x2+2x3+4x2+16+8x−2x3−8x−4x2=x4+4x2+16

Answered by Anonymous
8

Hope this helps

please mark me as brainlist

Attachments:
Similar questions