(x2+4-2x) (x2+4+2x)
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Answer :
x4+4x2+16
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(x2+4−2x)(x2+4+2x)
(x2+4−2x)(x2+4+2x)=(x2+4+−2x)(x2+4+2x)
(x2+4−2x)(x2+4+2x)=(x2+4+−2x)(x2+4+2x)=(x2)(x2)+(x2)(4)+(x2)(2x)+(4)(x2)+(4)(4)+(4)(2x)+(−2x)(x2)+(−2x)(4)+(−2x)(2x)
(x2+4−2x)(x2+4+2x)=(x2+4+−2x)(x2+4+2x)=(x2)(x2)+(x2)(4)+(x2)(2x)+(4)(x2)+(4)(4)+(4)(2x)+(−2x)(x2)+(−2x)(4)+(−2x)(2x)=x4+4x2+2x3+4x2+16+8x−2x3−8x−4x2
(x2+4−2x)(x2+4+2x)=(x2+4+−2x)(x2+4+2x)=(x2)(x2)+(x2)(4)+(x2)(2x)+(4)(x2)+(4)(4)+(4)(2x)+(−2x)(x2)+(−2x)(4)+(−2x)(2x)=x4+4x2+2x3+4x2+16+8x−2x3−8x−4x2=x4+4x2+16
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