Question

x²+4√3-63 solve by factorization

Answer 1

Question:

Solve by factorization:

$x^{2} + 4\sqrt{3} - 63$

Solution:

$p(x) = x^{2} + 4\sqrt{3}x - 63$

To factorize p(x)

$p(x) = x^{2} + 4\sqrt{3} - 63 = 0 \\ \implies x^{2} - 3\sqrt{3}x + 7\sqrt{3}x - 63 = 0 \\ \implies x(x - 3\sqrt{3}) + 7\sqrt{3}(x - 3\sqrt{3}) = 0 \\ \implies (x+7\sqrt{3})(x-3\sqrt{3}) = 0$

$x + 7\sqrt{3} = 0 \\ x = -7\sqrt{3}$

$x-3\sqrt{3} = 0 \\ x = 3\sqrt{3}$

Therefore, zeroes of $p(x) = x^{2} + 4\sqrt{3}x - 63$ are $-7\sqrt{3}$ and $3\sqrt{3}$.