Question

x²-4√3x-15=0 give me a polynomial step by step​

Answer 1

Step-by-step explanation:

Correct Question :- What is the zeros of the polynomial

${x}^{2} - 4 \sqrt{3} x - 15 = 0$

SOLUTION : -

$\implies \: {x}^{2} - 4 \sqrt{3} x - 15 = 0 \\ \\ \implies \: {x}^{2} - 5 \sqrt{3} x - \sqrt{3} x - 15 = 0 \\ \\ \implies \: x(x + 5 \sqrt{3} ) - \sqrt{3} (x + 5 \sqrt{3} ) = 0 \\ \\ \implies \: (x + 5 \sqrt{3} ) \: (x - \sqrt{3} ) = 0 \\ \\ \implies \: x = - 5 \sqrt{3} \: and \: \sqrt{3}$

The zeros of the given polynomial is -5√3 and √3 .

Answer 2

Answer:

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Step-by-step explanation:

Step 1: Let the unit's digit be x

Step 2: Then, ten's digit =(9−x)

∴ number =10×(9−x)+x⇒90−10x+x=(90−9x)

Step 3: Adding 27 to the number 90−9x we get 117−9x

Step 4: Number with digits interchanged is 10x+(9−x)=9x+9

Step 5: 117−9x=9x+9

Step 6: Therefore unit's digit=6 and ten's digit =3

Step 7: Hence the number =36.