Question

x²- 4 root 2x +6=0 solve by factorization ​

Answer 1

Answer:

x²-4√2x+6= 0

x²-3√2x-√2x+6=0

x²-3√2x-√2x+3*√2*√2=0 [ 6 = 3*2 = 3*√2*√2 ]

x(x-3√2)-√2(x-3√2)=0

(x-√2)(x-3√2)=0

x-√2 = 0, x = √2 and x-3√2 = 0, x= 3√2