Math, asked by Bhaveshyeole6446, 9 months ago

X²-46+17÷2, if the value of x is 7

Answers

Answered by vaishali2193
0

Answer:

hope it will help you out

Attachments:
Answered by gayatrikumari99sl
2

Answer:

11.5 is the required value of x^2 - 46 + 17 ÷ 2.

Step-by-step explanation:

Explanation:

Given in the question:

x^2 - 46 + 17÷ 2 and the value of x = 7.

So, from the question we need to find out the value of x^2 - 46 + 17÷2.

Step 1:

We have,   x^2- 46 + 17÷2.........(i)

Now, on putting the value of x = 7  in equation(i) we get,

x^2 - 46 + 17 ÷2

7^2 - 46 + 17 ÷ 2

According to BODMAS rule first we calculate division part,

⇒49 - 46 + \frac{17}{2} = 49 - 46 + 8.5

⇒49 -37 .5 = 11.5.

Final answer:

Hence, 11.5 is the required value of x^2 - 46+ \frac{17}{2}.

#SPJ2

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