Math, asked by tamannakumari961961, 4 months ago

x²-4ax+4a²-b²=0 question of quadratic equation ​

Answers

Answered by AgniPratap
1

Answer:

-4ax+4a²-b²=0

= (x)²-2×x×2a+(2a)²-b²=0

= (x-2a)²-(b)²=0

= (x-2a+b)(x-2a-b)=0

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