Question

. ;x2 - 4V2x + 6 = 0​

Answer 1

Answer:

${x}^{2} - 4 \sqrt{2} x + 6 = 0 \\ {x}^{2} - 3 \sqrt{2} x - \sqrt{2} x + 6 = 0 \\ x(x - 3 \sqrt{2} ) - \sqrt{2} (x - 3 \sqrt{2} ) = 0 \\ (x - 3 \sqrt{2} )(x - \sqrt{2} ) = 0 \\ so \: x = \sqrt{2} \: or \: 3 \sqrt{2}$

kimu

Answer 2

Answer:

this is correct..................