Question

للا
x2 + 4x + 1 = 0 (​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

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$\tt : \implies \: {x}^{2} + 4x + 1 = 0$

$\large \underline{ \underline{ \sf{ \color{orange}{solution}}}} \\ \\ \displaystyle \: \sf \: \longrightarrow \: d \: = {b}^{2} - 4ac \: \: \: \: \: \: \: \: \: \: \: \\ \\ \displaystyle \: \sf \: \longrightarrow \: d \: = {4}^{2} - 4 \times 1 \times 1 \\ \\ \displaystyle \: \sf \: \longrightarrow \: d \: = {16} - 4 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \displaystyle \: \sf \: \longrightarrow \: d \: = 12 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

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$\tt : \implies \: x = (- b + \frac{ \sqrt{d} }{2a} )\: \: (- b - \frac{ \sqrt{d} }{2a} )$