Math, asked by menemebe8749, 8 months ago

X2 - 4x + 1 = 0 find its roots

Answers

Answered by irshadsyed281
1

\bold{\blue{\underline{\red{G}\pink{iv}\green{en}\purple{:-}}}}\\\\

  • x² - 4x + 1 = 0
  • a = 1
  • b = - 4
  • c = 1

\bold{\blue{\underline{\red{Zeros}\pink{\:of\:}\green{\:the\:Quadratic\:equation}\purple{:-}}}}

  • Zeros of the quadratic equation is the value of the variable for which when replaced in the quadratic equations the value for the quadratic equation changes to zero.

\bold{\blue{\underline{\red{General}\pink{\:form \:of }\green{\:Quadratic\:equation}\purple{:-}}}}

  • ax² + bx + c = 0

\bold{\blue{\underline{\red{Q}\pink{uest}\green{ion}\purple{:-}}}}\\

  • Find the roots/zeros of the given equation.

\bold{\blue{\underline{\red{S}\pink{olut}\green{ion}\purple{:-}}}}

  • x² - 4x + 1 = 0
  • Quadratic formula = \bold{\frac{-b\: \pm\:{\sqrt{b^{2}\:-\:4ac} }}{2a}}  

  • α =  \bold{\frac{4\: \pm\:{\sqrt{-4^{2}\:-\:4(1)(1)} }}{2(1)}}  

  • α =  \bold{\frac{4\: \pm\:{\sqrt{16\:-\:4} }}{2}}

  • α = \bold{\frac{4\: \pm\:{\sqrt{12} }}{2}}  

  • α = \bold{\frac{4\: \pm\:2{\sqrt{3} }}{2}}

  • α =  \bold{2\: +\:{\sqrt{3} }}

  • β = \bold{2\: -\:{\sqrt{3} }}

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