Question

X2+4x-12 factorization

Answer 1

$= {x}^{2} + 4x - 12 \: \\ = {x}^{2} - 2x + 6x - 12 \\ = x(x - 2) + 6(x - 2) \\ = (x + 6)(x - 2) \\ \\ x = 2 \: and \: - 6$

Answer 2

${x}^{2} + 4x - 12 = 0 \\ {x}^{2} + 6x - 2x - 12 = 0 \\ x(x + 6) - 2(x + 6) = 0 \\ (x + 6)(x - 2) = 0 \\ x = - 6 \: \: \: \: or \: \: \: \: x = 2$
Hope it helps.