Question

X² - 4x + 13 = 0 , solve it by factorization method​

Answer 1

Answer:

Step-by-step explanation:

x² - 4x + 13 = x² - 4x + 4 + 9

= (x - 2)² - 9i²

= (x - 2)² - (3i)²

= (x - 2 - 3i)(x - 2 + 3i)

the zeroes of x² - 4x + 13 are 2 + 3i and 2 - 3i.

Answer 2

ASK

MATH MATH EQUATIONS

show x=2-3i is a solution of x^2-4x+13

 Can use quadratic formula which derives from factorization of quadratic: aX^2 + bX + c, by completing

 

   the square.

 

 X = -b/2a ±√( b^2 - 4ac)/ 2a

 

      X^2 - 4X + 13 = 0

 

          

 

      X = 4/ 2 ± √( 4^2 - 4(1)(13) / 2

 

       X = 2 ±√-36/ 2

 

           X = 2 ±6i/2

 

            X = 2 ± 3i

x2-4x+13=0

Let's factor the (x2-4)

(x-2)(x-2)

Let's FOIL...

FIRST...(x)(x)=x2

OUTER...(x)(-2)=-2x

INNER...(-2)(x)=-2x

LAST...(-2)(-2)=4

x2-2x-2x+4

x2-4x+4

Instead of +4, we need +13. (4+9)=13...

x2-4x+4+9=0

(x-2)2+9=0

Let's subtract 9 from both sides...

(x-2)2=-9

Let's square-root both sides...

x-2=√-9

x-2=3i

Let's add 2 to both sides...

x=2+3i

HOPE IT HELPS....