Math, asked by aashraye32, 19 hours ago

x2-4x+13 in factorisation method​

Answers

Answered by sunprince0000
1

Answer:x² - 4x + 13 = x² - 4x + 4 + 9

= (x - 2)² - 9i²

= (x - 2)² - (3i)²

= (x - 2 - 3i)(x - 2 + 3i)

the zeroes of x² - 4x + 13 are 2 + 3i and 2 - 3i.

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