Question

X²+4x+13

Pfvr. Preciso de ajuda isso tá muito difícil

Answer 1

Answer:

a equação não tem raízes reais

Answer 2

Step-by-step explanation:

x²+4x+13=0

Comparing above equation with general form,we get ,

a=1 , b=4 and c=13

Now,

b²-4ac = 4²- 4×1×13

=16-52

=36

x= - b±√b²-4ac / 2a

= -4±√36 / 2×1

= -4±6 /2

x= -4+6/2 or x = -4-6/2

= 2/2 = -10/2

= 1 =-5

1 and -5 are the roots of the given quadratic equation.