Question

x2 + 4x+16=0 solve by factorise method

Answer 1

$\textbf {ANSWER:}$

${x}^{2} + 4x + 16= 0 \\ \\ = > x(x + 4) = ( - 16) \\ \\ = > x + 4 = - 16x \\ \\ = > 4 = - 16x - x \\ \\ = > 4 = - 17x \\ \\ = > x = (- \frac{4}{17} )$

Answer 2

Hey Mate⭐⭐⭐

Here's ur answer ⤵⤵⤵

♦ x^2+4x+16=0

➡x^2+4x= -16

➡x (x+4)= -16

➡ x= -16

If x+4= -16

➡x= -20

✔✔✔Hope it will help you ☺☺☺