Question

x2-4x+3=0
give me ans fast​

Answer 1

${x}^{2} - 4x +3 = \: 0 \\ {x}^{2} - 3x - x + 3 = 0 \\ x(x - 3) - 1(x - 3) = 0 \\ (x - 3)(x - 1) = 0 \\ x - 3 = 0 \: \: \: \: \: \: \: \: \: x - 1 = 0 \\ x = 3 \: \: \: \: \: \: \: x = 1$

Answer 2

Answer:

(x-3)(x-1)

Step-by-step explanation:

x²-4x+3

=> x²- (3+1)x +3

=> x²-3x-x+3

=> x(x-3)-1(x-3)

=> (x-3)(x-1)