Question

x2+4x+3=0 nature of root​

Answer 1

Step-by-step explanation:

x^2 +4x +3=0

here a=1,b=4 ,c=3

(-b +√b^2-4ac)/2a

= (-1+√4^2-4×1×3)/2×1

=(-1+√16-12)/2

=(-1+√4)/2

= (-1+2)/2 or (-1-2)/2

= 1/2 or (-3)/2

explanation- (√4 = +2 or -2)

hope this will helpful.