Question

x² - 4x-3 =0 solve by factorization method​

Answer 1

${x}^{2} - 4x + 3 = 0 \\ {x}^{2} - 3x - x + 3 \\ x(x - 3) - 1(x - 3) \\ (x - 3)( x- 1) \\ \implies \: x = 3 \: or \: 1$

Hello mate !!

Ur q is wrong. It should be x²- 4x + 3.

Hope it helps !!