Question

x²-4x+3 find alpha⁴beta²+alpha²beta⁴​
please help me

Answer 1

Answer:

90

Step-by-step explanation:

As we know

x^2-4x+3=0

so x^2-3x-x+3=0

we get , x(x-3)-1(x-3)=0

so x=1 and x=3

here alpha and beta are roots of equation so alpha=1 and beta=3

on solving : (1)^4.(3)^2+(1)^2.(3)^4=9+81=90