X2-4x+3 find the zeroes of the polynomial and verify it by alpha and beta -b/a , c/a
sampadagupta:
is it X^2 ??
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x^2 - 4x +3 =p(x)
x^2 - 3x -1x + 3
x (x - 3) -1(x - 3)
(x - 1)(x - 3)
here the factors of p(x) are 1 andv3
alpha + beta = -b / a
1 + 3. = 4 / 1
and alpha * beta = c / a
1 * 3 = 3 / 1
hence proved
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