Question

X2-4x+3 find the zeroes of the polynomial and verify it by alpha and beta -b/a , c/a

Answer 1

x^2 - 4x +3 =p(x)

x^2 - 3x -1x + 3

x (x - 3) -1(x - 3)

(x - 1)(x - 3)

here the factors of p(x) are 1 andv3

$\alpha = 1 \: and \: \beta = 3$

alpha + beta = -b / a

1 + 3. = 4 / 1

and alpha * beta = c / a

1 * 3 = 3 / 1

hence proved