Question

x²-4x+3 find the zeros​

Answer 1

SOLUTION

$= > {x}^{2} - 4 + 3 \\ = > {x}^{2} - 3x - x + 3 = 0 \\ = > x(x - 3) - 1(x - 3) = 0 \\ = > (x - 3)(x - 1) = 0 \\ = > x - 3 = 0 \: \: \: \: \: \: \: or \: \: \: \: \: \: x - 1 = 0 \\ = > x = 3 \: \: \: \: \: \: or \: \: \: \: \: \: \: x = 1$

HOPE it helps ✔️