Question

X2-4x+3 find zeroes of polynomial and
Verify it by alpha and beta -b/a,. C/a

Answer 1

Answer:

Step-by-step explanation:

=X2-4x+3

=X2-x-3x+3 (by middle splitting method)

=X(x-1)-3(x-1)

=(x-1)(x-3)

If (x-1)=0

Then x=1

If (x-3)=0

Then x=3

Therefore zeroes are 1,3

VERIFICATION:

*Alpha + beta = 1+3=4

Alpha + beta = -b/a = -(-4)/1 = 4

*Alpha × beta = 1×3 = 3

Alpha ×beta = c/a = 3/1 = 3

Hence verified