Question

x²–4x +3 v2=0 are there any real roots ?​

Answer 1

Answer:

no real root exist

Step-by-step explanation:

x²–4x +3√2=0

x²-4x+3√2=0

D= b²-4ac

D = -4² - 4(1)(3√2)

D= 16-12√2

D = -0.97

here, D<0 therefore no real roots exists

Answer 2

Answer:

x² - 4x + 3√2 has no real roots but imaginary and distinct roots.

Step-by-step explanation:

If D = b² - 4ac > 0, equation has real and distinct roots.

If D = 0, equation has real and equal roots.

If D < 0, equation has imaginary and distinct roots.

Now, D = b² - 4ac

=> (-4)² - 4(1)(3√2)

=> 16 - 12√2

=> 16 - 12(1.414)

=> 16 - 16.968 => -0.968 which is less than 0.

As D < 0, x² - 4x + 3√2 has no real roots but imaginary and distinct roots.