Question

[x² - 4x + 4] by [x-2] = ?​

Answer 1

Answer:

first of all what does "by "means here is it Multiply or Divide. But I will do both for you.

Step-by-step explanation:

So here our question is :[x² - 4x + 4] by [x-2]

So taking by as Multiply:--

[x² - 4x + 4] * [x-2]

[(x² - 4x + 4)*x]-[(x² - 4x + 4)*2]

($x^{3}$-4x²+4x)-(2x²-8x+8)=$x^{3}$-6x²+12x-8

So now taking by as Divide:--

[x² - 4x + 4] / [x-2]

=x²−4x+4/x−2

=(x−2)(x−2) /x−2

So here we have common fctor as x-2 and x-2 at both sides

After solving our answer will beas

x−2

If you found my answer helpful please mark as the brainliest answer.

Answer 2

Step-by-step explanation:

$\LARGE{\underline{\underline{\pink{\bf{Solution:-}}}}}$

$\small\bf\green{☆Given, }$

To divide $x^2$-4x+4÷x-2

=$\frac{x^2-4x+4} {x-2}$

It can be seen that $x^2$-4x+4,

The second identity that is, $(x-y) ^2=x^2-2xy+y^2$

$\small\bf\green{☆So, }$

=$\frac{(x)^2-2(x)(2)+(2)^2} {x-2}$

=$\frac{(x-2)^2} {x-2}$

=$\frac{(x-2)(x-2)} {x-2}$

Cancelling x - 2 and x-2 in the numerator and denominator,

$\small\bf\green{☆We\:have, }$

(x-2)

∴ The answer is $\small\bf\green{(x-2)}$

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