Question

x2+4x-5=0 solve by quadratic equation​

Answer 1

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• Solve the quadratic equation.

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${x}^{2} + 4x - 5 = 0$

$\implies {x}^{2} - x + 5x - 5 = 0$

$\implies x(x- 1)+ 5(x - 1) = 0$

$\implies (x+ 5)(x - 1) = 0$

Therefore, either $x+5=0$ or $x-1=0$

Therefore,

$x + 5 = 0$

$\implies x = - 5$

Also,

$x - 1 = 0$

$\implies x = 1$

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• The roots of the equation are 1 and -5.

Answer 2

Answer:

X=1, -5

Step-by-step explanation:

For solution please refer attachment