Question

x²+4x+5 quadratic equetion ​

Answer 1

Answer: HEYY I HOPE Y ARE HAVING A WONDERFUL DAY/NIGHT.

PLEASE REFER TO ATTACHMENT, ITS SUPPOSE TO BE -4x

Answer 2

Answer:

your solution is as follows

pls mark it as brainliest

Step-by-step explanation:

$to \: find : \\ values \: of \: x \\ \\ given \: quadratic \: equation \: is \\ x {}^{2} + 4x + 5 = 0 \\ \\ comparing \: it \: with \\ ax {}^{2} + bx + c = 0 \\ we \: get \\ a = 1 \\ b = 4 \\ c = 5 \\ \\ we \: know \: that \\ ∆ = b {}^{2} - 4ac \\ \\ = (4) {}^{2} - (4 \times 1 \times 5) \\ \\ = 16 - 20 \\ \\ ∆ = - 4$

$we \: have \: \\ by \: shreedharacharya \: method \\ x = \frac{ - b \: ± \: \sqrt{b {}^{2} - 4ac } }{2a} \\ \\ = \frac{ - 4 \: ± \: \sqrt{ - 4} }{(2 \times 1)} \\ \\ = \frac{ - 4 \: ± \: 2i}{2} \\ \\ = \frac{2( - 2 \:± \: i) }{2} \\ \\x = - 2 \: ± \: i$