x²+4x-50=0 solve the quadratic equation
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Answer:
in this the discriminant is not a perfect square
so, x=[-4±√216]/2
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Answered by
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Answer:
x^2 + 4x - 50 = 0
We cannot solve it by factorisation method
We cannot solve it by factorisation methodSo, by formula method...
Here , a = 1 , b = 4 , c = -5 =b^2 - 4ac = 4^2 - 4 × 1 × (-50) = 16 - (-200) = 16 + 200
b^2 - 4ac = 4^2 - 4 × 1 × (-50) = 16 - (-200) = 16 + 200 =
216
We know that,
We know that,
x = - b +/- √b^2 - 4ac/2a = - 4 +/- √216 / 2 × 1
= - 4 +/- 12√3 /2
= -2 ( 2 +/- 6√3 )/2
= 2 gets cancelled
= 2+/- 6√3
therefore, x = 2 + 6√3 or 2 - 6√3
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