Question

√x²+4x-7 differentiate with respect to x​

Answer 1

Answer:

let y=√(x^2+4x-7)=(x^2+4x-7)^1/2

dy/dx=1/2(x^2+4x-7)^(1/2-1).(2x+4)

=1/2.2(x+2)(x^2+4x-7)^-1/2

=(x+2)/√(x^2+4x-7)

Answer 2

Answer:

dy/dx = (x+4)/√(x^2+4x-7)

Step-by-step explanation:

y = √(x^2+4x-7)

dy/dx = {1/2√(x^2+4x-7)}.d/dx.(x^2+4x-7)

dy/dx= {1/2√(x^2+4x-7)}.(2x+4).

or, dy/dx = (x+4)/√(x^2+4x-7).