Math, asked by vkeerthikritheeu, 4 months ago

(x²+4x-7)(x³-8x²+6x-11)

Answers

Answered by Anonymous

3

(x²+4x-7)(x³-8x²+6x-11)

= x²(x³-8x²+6x-11)+4x(x³-8x²+6x-11)-7(x³-

8x²+6x-11)

= x^5 - 8x^4+6x³-11x² +4x^4-32x³+24x²

-44x -7x³+ 56x²-42x+77

= x^5 - 4x^4 - 33x³ + 69x² - 86x + 77

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