Question

x² +4x -9 = (x+a)² +b find the value of a and b​

Answer 1

$\large\underline\purple{\bold{Solution :- }}$

$\tt \longrightarrow \: {x}^{2} + 4x - 9 = {(x + a)}^{2} + b$

$\tt \longrightarrow \: {x}^{2} + 4x + 4 - 4 - 9 = {(x + a)}^{2} + b$

$\tt\implies \: {(x + 2)}^{2} - 13 = {(x + a)}^{2} + b$

☆ On comparing, we get

$\tt\implies \:a \: = 2 \: and \: b \: = - \: 13$

Answer 2

Step-by-step explanation:

= x²+4x-9= x²+2ax+a² + b

= x²-x²4x-2ax-a² -b = 9

= 4x-2ax-a² - b =9

it is value of b

and x²+2ax+a² it is value of a