Question

x²-4x+k=0
pls ans!!!​

Answer 1

Answer:

The given quadratic equation is

x^2+4x+k=0x

2

+4x+k=0

A quadratic equation ax^2+bx+c=0ax

2

+bx+c=0 has real roots if

b^2-4ac\geq 0b

2

−4ac≥0

We have,

a=1,b=4,c=ka=1,b=4,c=k

(4)^2-4(1)(k)\geq 0(4)

2

−4(1)(k)≥0

16-4k\geq 016−4k≥0

16\geq 4k16≥4k

Divide both sides by 4.

4\geq k4≥k