Question

x²(4x³+3y)+y²(3x-9y+z) x=2; y=3​

Answer 1

Answer:

49/9

Step-by-step explanation:

if x=2, y=3,then

2*2(4*2*2*2+3)+3*3(3*2-9*3+z) =0

=4(35)+9(-21+z)=0

= 140+(-189+9z)=0

= -189+9z= -140

= 9z= -140+189

= z =49/9

hope this may help you; Thanks