(x2 – 4xy + y2).
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Answer:
⟹(
x
y
)
2
+4
x
y
+1=0
⟹
x
y
=
2
−4±2
3
=−2±
3
,
∴ The lines y=(−2+
3
)x and y=(−2−
3
)x and x−y=4 forms an equilateral triangle
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