Question

(x2-4xy-y2)(x-2y)where(x=3,y=2)

Answer 1

$( {x}^{2} - 4xy - {y}^{2} )(x - 2y) \\ \\ put \: x = 3 \\ y = 2 \\ \\ then \\ ({3}^{2} - 4 \times 3 \times 2 - {2}^{2} )(3 - 4) \\ 9 - 24 - 4 \times ( - 1) \\ 19$

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