Question

(x2-4xy-y2)(x-2y)where(x=3,y=2)

Answer 1

$\bold{Question}$

$( {x}^{2} - 4xy - {y}^{2} )(x - 2y)$

$Where \: x = 3 \:,\: y = 2$

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[Substitute the values of X and Y]

$( {3}^{2} - 4.3.2 - {2}^{2} )(3 - 2(2))$

$( 9 - 24 - 4)(3 - 4)$

$( - 19)( - 1)$

$- 19 \times - 1$

$[- \times - = +]$

$= 19$

$Therefore \: value \: of( {x}^{2} - 4xy - {y}^{2} )(x - 2y) = 19$