x² +4y² -z × - 1 /2 xyz
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Answer:
4x^2+y^2=40 …(1)
xy=6 or
4xy = 24 …(2)
Add (1) and (2): 4x^2+4xy+y^2 = (2x+y)^2 = 64 = 8^2, or
2x+y = 8 …(3)
From (3), y = 8–2x.
Thus xy = 6 = x(8–2x) =8x - 2x^2, or
2x^2 - 8x + 6 = 0, or
x^2 - 4x + 3 = 0, or
(x-1)(x-3) = 0 or x = 1 or 3 and so the corresponding value of y = 6 or 2.
Hence, with (x=1, y=6): 9x^2 + 4y^2 = 9+144 = 153.
with (x=3, y=2): 9x^2 + 4y^2 = 81+16 = 97.
Therefore, 9x^2 + 4y^2 is 153 or 97.
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Answer:
minus 1 by 2 X Y Z - 2 x y z + 1 by 2 x y z cube
Step-by-step explanation:
- X square + 4 y square - 2 x minus 1 by 2 x square this answer is minus 1 by 2 x cube minus 2 x y cube Z + 1 by 2 X Y Z Square
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