Question

x²+4y²+z²+4xy-2xz-4yz​

Answer 1

Step-by-step explanation:

x^2 + 4y^2 + z^2 + 4xy - 2xz - 4yz

Using identity

(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca

= (x)^2 + (2y)^2 + (-z)^2 + 2*(x)*(2y) + 2*(x)*(-z) + 2*(2y)*(-z)

= (x + 2y - z)^2

= (x + 2y - z)(x + 2y - z)