Question

x²-5/2x+3/2=0
Solve by any method​

Answer 1

In context to questions asked

We have to determine the value of X

As per questions

We have

${x}^{2} - \frac{5}{2} x + \frac{3}{2} = 0$

Now, multiplying each terms by 2

We will get,

$2 \times {x}^{2} - 2 \times \frac{5}{2} x + 2 \times \frac{3}{2} = 0 \\ 2 {x}^{2} - 5 x + 3 = 0$

Now solving the obtained expression by splitting the middle term

We will get

$2 {x}^{2} - 5x + 3 = 0 \\ 2 {x}^{2} - 2x - 3 x+ 3 = 0 \\ = > 2x(x - 1) - 3(x - 1) = 0 \\ = > (2x - 3)(x - 1) = 0 \\ = > x = \frac{3}{2} \: and \: 1$

Hence, value of X will be 3/2 and 1.

Answer 2

Answer: the values of x is 1.5 or 1

Step-by-step explanation:

Given, x²-5/2x+3/2=0

⇒2x² - 5x + 3 = 0 [multiplying by 2]

⇒2x² - (3+2)x + 3 = 0

⇒2x² - 3x - 2x + 3 = 0

⇒x(2x - 3) - 1(2x - 3) = 0

⇒(2x - 3)(x - 1) = 0

Then, 2x - 3 = 0 or x - 1 = 0

⇒x = 3/2 ⇒x = 1

⇒x = 1.5