x²+√5 find the zeros of the polynomial
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Given quadratic polynomial,
↪ x² + √5 = 0
Let,
- a = 1
- b = 0
- c = √5
➡ Sum of the zeroes : α + ß = -b/a = -0/1 = 0
➡ Product of the zeroes : αß = c/a = √5/1 = √5
Hence, it is solved...
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