Question

x²+5 has bo real zeroes why? Give reason
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Answer 1

ANsWeR :-

x2+1, has discriminant =b2−4ac=0

2−4(1)(1)=−4<0

So, this has no real roots,

Hence it has no zeroes

Answer 2

Answer:

x²+5 has no real zeroes.

Step-by-step explanation:

$x^2 +5$, has  discriminant $= b^2 -4ac$

$=0^2 -4(1)(5)=-20 < 0$

So, this has no real roots,

Hence it has no zeroes,