x²+5 has bo real zeroes why? Give reason
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Answered by
1
ANsWeR :-
x2+1, has discriminant =b2−4ac=0
2−4(1)(1)=−4<0
So, this has no real roots,
Hence it has no zeroes
Answered by
11
Answer:
x²+5 has no real zeroes.
Step-by-step explanation:
, has discriminant
So, this has no real roots,
Hence it has no zeroes,
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