Math, asked by zeeshan82md, 2 months ago

x²+5 has bo real zeroes why? Give reason

Answers

Answered by MissPhenomenal
1

ANsWeR :-

x2+1, has discriminant =b2−4ac=0

2−4(1)(1)=−4<0

So, this has no real roots,

Hence it has no zeroes

Answered by preeti353615
11

Answer:

x²+5 has no real zeroes.

Step-by-step explanation:

x^2 +5, has  discriminant = b^2 -4ac

=0^2 -4(1)(5)=-20 &lt; 0

So, this has no real roots,

Hence it has no zeroes,

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