Question

x2+5(x+1)=0 by any method
Please solve this problem​

Answer 1

Answer:

The value of $x$ in $x^{2} +5(x+1)=x^{2} +5x+5=0$ is

$x=\frac{5+\sqrt{5} }{2}$ or $x=\frac{5-\sqrt{5} }{2}$

Step-by-step explanation:

We can solve this problem by using the quadratic formula

$x=\frac{-b}{2a}$±$\frac{\sqrt{b^{2}-4ac } }{2a}$.

here $a=1,b=5,c=5$

substituting these values in the formula we get

$x=\frac{5}{2}$±$\frac{\sqrt{5^{2}-4(1)(5) } }{2}$

$=\frac{5}{2}$±$\frac{\sqrt{5} }{2}$.

hence the answer.

thank you