Question

X2+5has no real zero why​

Answer 1

Given equation is x^2 + 5

or, x^2 +0x + 5

Now,

if D(b^2-4ac) is less than 0, then Equation has no real roots or no real zero.

D = 0^2 - 4(1)(5)

or, D= 0-20 = -19.

Since D is less than zero , equation has no real zeros.

Therefore, x^2+5 has no real zero.