Question

x2 + 5x - 1 = 0 ; Solve by formula method. quadratic equation​

Answer 1

Step-by-step explanation:

$by \: sridharacharya \: method \\ x = \frac{ - b \binom{ + }{ - } \sqrt{ {b}^{2} - 4ac} }{2a} \\ now \: from \: given \: question \\ {x}^{2} + 5x - 1 = 0 \\ a = 1 \: \: \: b = 5 \: \: \: c = - 1 \\ \\ then \: putting \: all \: these \: values \: in \: the \: formula \: \\ x = \frac{ - 5 \binom{ + }{ - } \sqrt{ {5}^{2} - 4 \times 1 \times ( - 1)} }{2 \times 1} \\ x = \frac{ - 5 \binom{ + }{ - } \sqrt{25 + 4} }{2 } \\ x = \frac{ - 5 \binom{ + }{ - } \sqrt{29} }{2 } \\ \\ x = \frac{ - 5 + \sqrt{29} }{2} \: \: \: \: \: \: x = \frac{ - 5 - \sqrt{29} }{2}$

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