Question

x²-5x+10= 5(x²–5x+4)½​

Answer 1

Step-by-step explanation:

x²-5x+10= 5(x²–5x+4)½

=> (x²-5x+10)/5 = (x²–5x+4)½

=> [(x²-5x+10)/5]² = (x²–5x+4)

=> 1/25 ($x^4$ + 25x² + 100 - 10$x^3$ - 100x + 10$x^2$) = (x²–5x+4)

=> ($x^4$ + 25x² + 100 - 10$x^3$ - 100x + 10$x^2$) = 25(x²–5x+4)

=> $x^4$ + 25x² + 100 - 10$x^3$ - 100x + 10$x^2$ = 25x² - 125x + 100

=> $x^4$ - 10$x^3$  + 10$x^2$ + 125x - 100x = 0

=> $x^4$ - 10$x^3$  + 10$x^2$ + 25x = 0

=> $x^3$ - 10$x^2$ + 10x + 25 = 0