x²-5x+10= 5(x²–5x+4)½
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Step-by-step explanation:
x²-5x+10= 5(x²–5x+4)½
=> (x²-5x+10)/5 = (x²–5x+4)½
=> [(x²-5x+10)/5]² = (x²–5x+4)
=> 1/25 ( + 25x² + 100 - 10
- 100x + 10
) = (x²–5x+4)
=> ( + 25x² + 100 - 10
- 100x + 10
) = 25(x²–5x+4)
=> + 25x² + 100 - 10
- 100x + 10
= 25x² - 125x + 100
=> - 10
+ 10
+ 125x - 100x = 0
=> - 10
+ 10
+ 25x = 0
=> - 10
+ 10x + 25 = 0
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