Question

x2−5x+6=0 by formula method

Answer 1

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$\underline{SOLUTION}$ ➡

$Formula \: \: Method \: : - \\ \\ \boxed{ x = \frac{ - b± \sqrt{b {}^{2} - 4ac } }{2a} }$

$Now, \\ \\ Given \: : x {}^{2} - 5x + 6 = 0 \\ \\ Here, \\ \\ a = 1 \\ \\ b = - 5 \\ \\ c = 6$

$Putting \: \: the \: \: values \: \: of \: \: a\: , \: b \:\: and \: \: c \: \: \\ in \: \: the \: \: formula \: \: method \: :-$

$We \: \: get ,$

$x = \frac{ - b± \sqrt{b {}^{2} - 4ac } }{2a} \\ \\ = \frac{ - ( - 5)± \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6} }{2 \times 1} \\ \\ = \frac{5± \sqrt{25 - 24} }{2} \\ \\ = \frac{5± \sqrt{1} }{2} \\ \\ = \frac{5±1}{2}$

$Therefore, \\ \\ x = \frac{5±1}{2} \\ \\ So, \\ \\ x = \frac{5 +1 }{2} \\ \\ = > x = \frac{6}{2} \\ \\ = > x = 3 \\ \\ Or , \\ \\ x = \frac{5 - 1}{2} \\ \\ = > x = \frac{4}{2} \\ \\ = > x = 2$

$\underline{ANSWER}$ ➡ $\boxed{ x = 3 \: , \: x = 2 }$

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Answer 2

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