Math, asked by bushranabeeha, 3 months ago

X²–5x+7/(x-1)^4=A/(x-1)+B/(x-1)^2+C/(x-1) ^3+D/(x-1) ^4 then A+B+C+D=

Answers

Answered by kanishkaverma1952
1

Step-by-step explanation:

A=0

B=1

C=-3

D=3

A+B+C+D=0+1+(-3)+3

A+B+C+D=1

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