Question

x2 + 5x - (a+a-6) = 0 please answer right ​

Answer 1

Heya friend,

L.H.S.

⇒ $x^{2} + 5x - (a^{2} + a - 6 )$

There can we number of ways to solve this like :-

• Solving the quadratic equation of variable 'a' first which is given in the equation.
• Or, simply putting the values in the discriminant method.

So,

We know,

d = $b^{2} - 4ac$

  = $5^{2} - [-4(1)(a^{2} +a-6)]$

  = $25 + 4a^{2} + 4a -24$

  = $4a^{2}+4a+1$

  = $(2a+1)^{2}$                            

and x = ( - b ± $\sqrt{d}$  ) / 2a

         = ( - 5 ±  $\sqrt{(2a+1)^{2} }$ ) / 2 (1)

         = ( - 5 ± 2a + 1 ) / 2

So,

x is either of the two values :-

x = $\frac{-5 + (2a + 1)}{2}$                            OR                             x = $\frac{- 5 - (2a + 1)}{2}$

x= $\frac{-5 + 2a + 1}{2}$                               OR                             x = $\frac{-5-2a-1}{2}$

x=$\frac{2a-4}{2}$                                      OR                             x = $\frac{-2a-6}{2}$

x = $\frac{2(a-2)}{2}$                                  OR                             x = $\frac{-2(a+3)}{2}$

So,

x = ( a-2 ) ,  (-a-3)  

Thanks!

#BAL #answerwithquality