Question

x2+5x_(a2+a_6)=0 solve for x

Answer 1

Given: The equation x² + 5x - (a² + a - 6 ) = 0

To find: Solve for x?

Solution:

• Now we have given the equation:

                   x² + 5x - (a² + a - 6 ) = 0

                   x² + 5x - (a² + 3a - 2a - 6 ) = 0

                   x² + 5x - (a(a+3) - 2(a+3)) = 0

                    x² + 5x - (a+3)(a-2) = 0

• Now 5x can be written as:

                   5x = [(a+3) - (a-2)]x

                    x² + [(a+3) - (a-2)]x - (a+3)(a-2) = 0

                    x² + (a+3)x - (a-2)x - (a+3)(a−2) = 0

                    x[x+(a+3)] - (a-2)[x+(a+3)] = 0

                    [x+(a+3)] [x−(a−2)]=0

• Now, either  [x+(a+3)] = 0 or [x−(a−2)] = 0

                   x = -(a+3) or x = (a-2)

Answer:

                So the value of x is -(a+3) or (a-2)