x²+5x+k if a and b the zeros of polynomial of a-b=1
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equation
x²+5x+k
a+b=-b/a.
a+b= -5. eq (1)
and
a*b=c/a
a*b=k eq (2)
a-b=1. (given)
(a-b)²=1. { (A-B)²=A²+B²-2AB}
both side square
a²+b²-2ab=1
a²+b²-2ab+2ab=1+2ab.
add (2ab) both side
(a+b)²-4ab=1. [ (A+B)²=A²+B²+2AB ]
from equation (1) and (2)
(-5)²-4k=1
25-4k=1
-4k= - 24
4k=24
k=6
hope its helpful
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