Question

x²-6 dint t relationship between the roots and coiefecient
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Answer 1

Step-by-step explanation:

First of all, we have to find the zeroes of the given quadratic polynomial.......

x^2-6 = (x-√6)^2 or (x-√6)(x+√6)

hence, zeroes are -√6, √6

So, we observe that -√6 and √6 are the zeroes

Observe that:

Sum of zeroes = -√6+√6= 0 = 0/1. -(coefficient of x/coefficient of x^2)

Product of zeroes = -√6*√6 = -6= -6/1. (constant term/coefficient of x^2)

Therefore here is the required relationship between the roots and the coefficient.