Math, asked by vedachaudhary0, 3 months ago

x²-64 factorize using suitable identity​


AVINAB786: Sorry there is one mistake. I write (x-y)(x+y) in the case of (x+8)(x-8)

Answers

Answered by AVINAB786
1

Answer:

(x-8)(x+8)

Step-by-step explanation:

.X'2-64

=X'2-8'2

=(X-8)(X+8)

HOPE YOU GOT YOUR ANSWER...

Answered by NishikaChauhan
2

Answer:

  {x}^{2}  - 64 \\  {x}^{2}  -  {8}^{2}  \\  ({a}^{2}  -  {b}^{2}  = (a - b)(a + b)) \\( x - 8)(x + 8)

Step-by-step explanation:

Hope it helps you

Similar questions