x²-64 factorize using suitable identity
AVINAB786:
Sorry there is one mistake. I write (x-y)(x+y) in the case of (x+8)(x-8)
Answers
Answered by
1
Answer:
(x-8)(x+8)
Step-by-step explanation:
.X'2-64
=X'2-8'2
=(X-8)(X+8)
HOPE YOU GOT YOUR ANSWER...
Answered by
2
Answer:
Step-by-step explanation:
Hope it helps you
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